x^2+2-(2x)=x-2-(-x^2-1)

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Solution for x^2+2-(2x)=x-2-(-x^2-1) equation: 



x^2+2-(2x)=x-2-(-x^2-1)

We move all terms to the left:

x^2+2-(2x)-(x-2-(-x^2-1))=0



We calculate terms in parentheses: -(x-2-(-x^2-1)), so:

x-2-(-x^2-1)

determiningTheFunctionDomain
-(-x^2-1)+x-2

We get rid of parentheses

x^2+x+1-2

We add all the numbers together, and all the variables

x^2+x-1

Back to the equation:

-(x^2+x-1)



We add all the numbers together, and all the variables

x^2-2x-(x^2+x-1)+2=0

We get rid of parentheses

x^2-x^2-2x-x+1+2=0

We add all the numbers together, and all the variables

-3x+3=0

We move all terms containing x to the left, all other terms to the right

-3x=-3

x=-3/-3

x=1

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